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alexgriva [62]
3 years ago
12

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y–1 = (x – 12). What is the

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

x - 4y = 8

Step-by-step explanation:

put (-4;-3) and (12;1) into the equation that in the multiple choice.

so, Example we choose the first equation:

x - 4y = 8 / (-4;-3). (12;1)

-4-4(-3)=8. 12-4(1)=8

-4+12=8. 12-4=8

so,. 8=8 is collect. 8=8 is collect also

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Step-by-step explanation:

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Hope this helps.

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The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit
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Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b) We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean \mu, standard deviation \sigma

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b. If the length of pregnancy is in the lowest a​%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

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Water stations will be placed every 600 meters of a fifteen kilometer race how many water stations will be needed
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