The horizontal distance is given by the formula:
tan θ=opposite/adjacent
where:
θ=21
opposite=2000 ft
adjacent=a
thus calculating for a we get:
tan 21=2000/a
thus
a=2000/tan 21
a=5210.18 ft
Answer: 5210.18 ft
Answer:
y=3x+13
Step-by-step explanation:
Answer;
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
Step-by-step explanation:
The complete question is as follows;
For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05
Solution is as follows;
Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.
Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
B is the answer hope this helps
Answer:
No, its C. G+15+8=45
Step-by-step explanation:
Because 1/3 of 45 is 15 is the amount of fuji apples, and 8 are red delicious, the rest are the amount of granny smiths.
