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Vilka [71]
2 years ago
10

What is the area of a square with a side length of 10cm?

Mathematics
2 answers:
AURORKA [14]2 years ago
7 0

Answer:

100 cm

Step-by-step explanation:

the area of a quadrilateral is length times width, but for a square those values should be the same.

therefore, 10 times 10 is 100.

natita [175]2 years ago
4 0

Answer:

100cm

Step-by-step explanation:

10*10

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romanna [79]

Answer:

D 0.00000256

Step-by-step explanation:

5^{28} *5^{-32}*5^{-4}=5^{28-32-4}=5^{-8}=\frac{1}{5^{8}} =0.00000256

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2 years ago
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Somebody please help me
Elenna [48]

Answer:

I believe it's 4,080

Step-by-step explanation:

you just add the two numbers

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If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?
irina [24]

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV

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6 0
1 year ago
Find the value of m and b for the equation 0=-9x+5y+25
lukranit [14]

Answer:

X= -5

Y=-2.7

Step-by-step explanation:

YOU DO THIS BY SUBTRACTING 25 ON THE RIGHT SIDE TO THE LEFT ONLY LEAVING YOU WITH VARIABLES.

THEN YOU SUBSTITUTE ZERO INTO Y TO FIND X THEN SUBTITUTE ZERO INTO X TO FIND Y

BTW SUBSTITUTE ONE INTO THE VARIABLE YOU ARE FINDING

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SoIve the system of equations by elimination. (Addition)<br> 1)-2x + 4y = -22<br> 2x + 8y = –26
Rufina [12.5K]

Answee:

We have these two equations:

-2x +4y =-22

2x + 8y -26

We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:

2x + 8y =-26  ---- -2x - 8y =26

Now we have this:

-2x +4y = -22

-2x -8y = 26

Now e substract both equations:

-2x - (-2x) +4y -(-8y) = -22-26

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Y = -48/12 = -4

And we replace to get x

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