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Kamila [148]
2 years ago
10

Pls pls help me answer ii put this attachment

Mathematics
1 answer:
trasher [3.6K]2 years ago
3 0

Answer:

1/4 is ur answer :)

Step-by-step explanation:

Hoped It Helped

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Solve for n. (7^2)^4 = n^8
enyata [817]
7^2x4 = n^8
7^8 = n^8
n = 7
4 0
3 years ago
Simplify the giving expression<br>(18/12 t-8)2<br>​
bekas [8.4K]

Answer:

3t - 16

Step-by-step explanation:

(18/12 t-8)*2

First simplify inside the parentheses

(3/2 t -8)*2

Then multiply

3/2t *2 -8*2

3t - 16

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3 years ago
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FACTOR the expression 6x+3y-12 using the greatest common multiple.
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

For 6x+3y-12 the greatest common factor is 3 so

3(2x+y-4)

For -2+6x+4+4x

10x+2 and 2 is greatest common factor so

2(5x+1)

8 0
3 years ago
Hi! I would really appreciate it if you can help me with this problem.
miss Akunina [59]
GCF: 2v5
2v5(4v+1+5v4)
7 0
3 years ago
What type of triangle has side lengths 9, 10, and √130? A. obtuse B. not a triangle C. acute D. right
EastWind [94]

Answer: Option C.

Step-by-step explanation:

The lengths of our triangle are:

9, 10 and √130.

If the triangle is a triangle rectangle, by the Pitagoream's theorem we have:

A^2 + B^2 = H^2

in this case H is the larger side, this must be √130.

then:

A and B must be 9 and 10.

9^2 + 10^2 = (√130)^2

81 + 100 = 130

This is false, so this is NOT a triangle rectangle, the hypotenuse is shorter than it should be.

Now, we have some kind of rule:

 if A^2 + B^2 = H^2 then we have one angle of 90° and two smaller ones. (triangle rectangle)

 if A^2 + B^2 > H^2 then all the angles are smaller than 90°, this is an acute triangle.

 if A^2 + B^2 < H^2 then we have one angle larger than 90°, this is an obtuse angle.

(H is always the larger side, A and B are the two shorter ones).

In this case:

81 + 100 > 130

Then this must be an acute angle.

3 0
3 years ago
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