Answer:
Step-by-step explanation:
Let us assume that if possible in the group of 101, each had a different number of friends. Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.
Say P has 100 friends then P has all other persons as friends. In this case, there cannot be any one who has 0 friend. So a contradiction. Hence proved
Part ii: EVen if instead of 101, say n people are there same proof follows as
if different number of friends then they would be 0,1,2...n-1
If one person has n-1 friends then there cannot be any one who does not have any friend.
Thus same proof follows.
Factor of 6x are 1,2,3,6,x,2x,3x,6x (Answer)
Answer:
90
Step-by-step explanation:
<0____1____2___3___4____5____6___>
■■■■■■■■■■■■■o------------------------------>
o-------------------> = graph
Answer: <u><em>188 pairs of rabbits would be produced after fourteen months</em></u>
<u><em></em></u>
Given: Newborn rabbits become adults in one month.
Each pair of adult rabbits produces one pair each month.
No rabbits die.
The Fibonacci sequence can be written as :
= 0 1 1 2 3 5 8 13 21 34 ..........................
This series can be further written as:
= 
Therefore for n = 14;
<u><em>
= 377</em></u>
