<span>g^2 – 4g – 21 = (g – 7)(g +3 )
hope it helps</span>
14. The equation would be -16t^2+60t+7 To find the maximum point plug in values into the equation -b/2a to find the axis of symmetry, and plug that number in for t.
b=60, a=-16
-60/-32=t=1.875
-16(1.875)^2+60(1.875)+7=63.25
Maximum point: (1.875,63.25)
The ball will land after about 3.86 seconds
A = P + SI
A-P = SI
5425-5000 = 425
THEREFORE THE SIMPLE INTRESTE IS $425
SI = PTR/100
425 = 5000×1×R/100
425×100/5000×1=R
425×100÷5,000×1 = 8.5%
THEREFORE THE RATE IS 8.5%
Answer:
k = 3.
Step-by-step explanation:
If they are collinear the slope of AB = the slope of BC, so :-
(0- (-2)) / (2 - 0) = (k - 0) / (5 - 2)
2/2 = k/3
1 = k/3
k = 3.
