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snow_lady [41]
3 years ago
6

There are 5 yellow marbles and 6 blue marbles in a bag. You randomly choose one of the marbles. What is the probability of choos

ing a yellow marble? Write your answer as a fraction in simplest form. The probability of choosing a yellow marble is
Mathematics
2 answers:
Nat2105 [25]3 years ago
8 0

Answer:

The probability of choosing a yellow marble is 5/11

Step-by-step explanation:

add 5 and 6 together. it equils 11. Five out of the 11 marbles are yellow.  that means it is (5, 11) or 5/11. This cannot be simplified any more than it is.

Ad libitum [116K]3 years ago
7 0

Answer

\frac{5}{11}

Step-by-step explanation:

The total number of marbles is 11 because 5+6=11. Since that is the total, 11 is the denominator. The question is asking for the probability of choosing a yellow marble. There are 5 yellow marbles, so 5 is the numerator. \frac{5}{11}

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Part 1:
Gnom [1K]
P = 2(L + W)
L = 4/3W

P = 2(4/3W + W) <=== part 1 is D

when P = 28
28 = 2(4/3W + W)
28/2 = 4/3W + 3/3W
14 = 7/3W
14 / (7/3) = W
14 * 3/7 = W
42/7 = W
6 = W....width is 6 inches

L = 4/3W
L = 4/3(6)
L = 24/3
L = 8....length is 8 inches

A = L * W
A = 8 * 6
A = 48 in^2 <==== part 2

7 0
3 years ago
What is the greatest possible product of a 2 digit number and a 1 digit number?
ss7ja [257]
99 x 9 = 891 I think
5 0
3 years ago
Juan earns $11 per hour and works at the most 30 hours per week. Identify the independent and dependent quantity in the situatio
yanalaym [24]
Independent: Hours (Domain)

Dependent: Money (Range)

Domain: [0,30]
Range: [0,330]
7 0
3 years ago
Read 2 more answers
In △ABC, point D∈ AC with AD:DC=4:3, point E∈ BC so that BE:EC=1:5. If ACDE=5 in2, find ABDC, AABD, and AABC.
Kaylis [27]

Answer:

ar ΔBDC=6 in^2

ar ΔABD=8 in^2

ar ΔABC=14 in^2

Explanation:

Please take a look of attach figure.

We are given area of triangle ar ΔCDE=5 in^2

ar ΔCDE=\frac{1}{2}\times DN\times EC------------(1)

ar ΔBDE=\frac{1}{2}\times DN\times BE------------(2)

Divide eq(2) by eq(1) and we get,

\frac{ar\ ΔBDE}{ar\ ΔCDE}=\frac{BE}{EC}

\frac{ar\ ΔBDE}{5}=\frac{1}{5}

So, ar ΔBDE=1 in^2

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ar ΔBDC=1+5 = 6 in^2

Similarly,

\frac{ar\ ΔABD}{ar\ ΔBDC}=\frac{AD}{DC}

\frac{ar\ ΔABD}{6}=\frac{4}{3}

ar ΔABD=8 in^2

ar ΔABC=ar ΔABD + ar ΔBDC

ar ΔABC=8+6 = 14 in^2

6 0
3 years ago
Write equivalent fractions for 1/4,1/2,and 7/9 using the least common denominator.
Oduvanchick [21]

The lowest common denominator is 36

1/4 = 9/36

1/2 = 18/36

7/9 = 28/36

If this is correct, Please leave a Thanks!

It Helps! :)

5 0
2 years ago
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