P = 2(L + W)
L = 4/3W
P = 2(4/3W + W) <=== part 1 is D
when P = 28
28 = 2(4/3W + W)
28/2 = 4/3W + 3/3W
14 = 7/3W
14 / (7/3) = W
14 * 3/7 = W
42/7 = W
6 = W....width is 6 inches
L = 4/3W
L = 4/3(6)
L = 24/3
L = 8....length is 8 inches
A = L * W
A = 8 * 6
A = 48 in^2 <==== part 2
Independent: Hours (Domain)
Dependent: Money (Range)
Domain: [0,30]
Range: [0,330]
Answer:
ar ΔBDC=6 
ar ΔABD=8 
ar ΔABC=14 
Explanation:
Please take a look of attach figure.
We are given area of triangle ar ΔCDE=5 
ar ΔCDE=
------------(1)
ar ΔBDE=
------------(2)
Divide eq(2) by eq(1) and we get,


So, ar ΔBDE=1 
ar ΔBDC=ar ΔBDE+ ar ΔCDE
ar ΔBDC=1+5 = 6 
Similarly,


ar ΔABD=8 
ar ΔABC=ar ΔABD + ar ΔBDC
ar ΔABC=8+6 = 14 
The lowest common denominator is 36
1/4 = 9/36
1/2 = 18/36
7/9 = 28/36
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