Answer:
Step-by-step explanation:
there are infinite numbers between 2 and 3 having average=2.5
2.49,2.51
2.48,2.52
2.47,2.53
2.46,2.54
.................
2.491,2.509
2.492,2.508
2.493,2.507
......................
Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³
A(10) = <span>9(10) + 9= 90+9 =99
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Answer:
a. -5
b.-5
c.-5
Step-by-step explanation:
In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.
Generally, the average rate of change (ARC) on an ecuatios between two points (x1,f(x1)) and (x2,f(x2)) is
- ARC = [f(x2)-f(x1)]/ (x2-x1)
<em>In case a)</em>
f(-1)= -5*(-1)-8=5-8= -3 f(3)= -5*3-8= -23
Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5
<em>In case b)</em>
f(a)= (-5a-8)
f(b)= (-5b-8)
Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5
<em>In case c)</em>
f(x)= -5x-8
f(x+h)= -5(x+h)-8= -5x-5h-8
then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5
Answer:
y = 57
Step-by-step explanation:
y α x
y = kx ; k = Constant of proportionality
81 = k* 54
k = 81/54
k = 1.5
Value of y when x = 38
y = kx
y = 1.5 * 38
y = 57
Hence, y = 57 when x = 38
