Answer:
Step-by-step explanation:
log3(x^2)-log3(x+4)=4
Log 3(x^2/x+4)=4 -Combine the logs
x^2/x+4 = 3^4 - Use the relationship Logb(y)=x =>b^x=y
x^2/x+4 = 81
x^2= 81^(x+4)
x^2=81x+324
x^2-81x-324=0
Solving for x using the property x=-b-/+[tex]\sqrt{x} b^2-4ac]/ 2a
=(81 ±√(81)^2-4^11^324)/2
= (81±√6561-1296)/2
=(81±88.63)/2
= (81+88.63)/2
=84.81
Answer:
y =
Step-by-step explanation:
Given
2(3y + 5) = 3(5y + 3) ← distribute parenthesis on both sides
6y + 10 = 15y + 9 ( subtract 6y from both sides )
10 = 9y + 9 ( subtract 9 from both sides )
1 = 9y ( divide both sides by 9 )
= y
About 6406 people will be subscribed because every month 146 people join
Answer:
The answer to your question is: the points are not collinear.
Step-by-step explanation:
Data
AB = 7
BC = 4
AC = 9
Are points A,B and C collinear?
If they are collinear, the distance from AB plus the distance BC must be equal to the distance AC.
Process
dAB + d dBC = d AC
7 + 4 = 9
11 = 9
The distances are different so they are no collinear