The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of
- height, h = apothem of the hexagon = 2 cm and
- base, b = length of shorter base of trapezoid.
<h3>Area of the triangle</h3>
So, the area of this triangle is A = 1/2bh
= 1/2 × 1. 5 cm × 2 cm
= 1.5 cm × 1 cm
= 1.5 cm²
<h3>Area of the hexagon</h3>
Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A
= 6 × 1.5 cm²
= 9.0 cm²
So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Learn more about area of a hexagon here:
brainly.com/question/369332
For the function f ( x ) = x² we have the new function f 1 ( x ) = 1/2 x².
f ( x ) = a · x²
- If |a| < 1 the graph is compressed vertically by a factor of a.
- If |a| > 1 the graph is stretched vertically by a factor of a.
Here: a = 1/2 < 1
Answer:
C. The graph will be compressed vertically.
There are numerous ways you can do this, but take a look at the attachment to see how I did it. I hope it answers your question! :)
Your answer will be 12 since 8/8 is one whole and you need 12 so your answer is 12
