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almond37 [142]
3 years ago
15

What is 52% of 25?

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

13

Step-by-step explanation:

25 x 0.52 = 13

Basile [38]3 years ago
5 0
<h2>Answer:</h2><h2>13</h2>

Step-by-step explanation:

52 \% \times 25\\\\\frac{52}{100} \times 25\\0.52 \times 25\\= 13\\\\\frac{52}{100} \times 25\\Use ; 25 -to -divide -;100\\= 52/4\times 1/1\\= \frac{52}{4} \\\\= 13\\

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Letter d is the answer.
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Jong earnee $100, and saved $30. What decimal part did he save
Readme [11.4K]

Answer:

Hi, this question is a little unclear.  If you want to know what percentage he saved, it would be 30%, and to convert that percentage into a decimal would be a decimal of 0.30

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3. Sam and Tim each have savings accounts. Every month they each put in some of their
Setler [38]

Answer:

y = 30x +50 --- Sam

y = 20x +80 --- Tim

Step-by-step explanation:

Given

Sam                         Tim

х  --- f(x) ---------------  g(x)

1  --- 80   --------------- 100

2  --- 110  --------------- 120

3  --- 140 --------------- 140

4 --- 170 -------------- 160

Required

Determine the y value

y value implies the equation of the table

Calculating the equation of Sam

First, we need to take any corresponding values of x and y

(x_1,y_1) = (1,80)

(x_2,y_2) = (4,170)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{170 - 80}{4 - 1}

m = \frac{90}{3}

m = 30

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 80 = 30(x - 1)

y - 80 = 30x - 30

Make y the subject

y = 30x - 30 + 80

y = 30x +50

Calculating the equation of Tim

First, we need to take any corresponding values of x and y

(x_1,y_1) = (1,100)

(x_2,y_2) = (4,160)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{160 - 100}{4 - 1}

m = \frac{60}{3}

m = 20

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 100 = 20(x - 1)

y - 100 = 20x - 20

Make y the subject

y = 20x - 20+100

y = 20x +80

7 0
3 years ago
Can someone help me answer this?
Masja [62]

Your answer is angle JCL.

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3 0
3 years ago
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Line HF is tangent to circle D at point E. SEgment DE is the radius of circle D, what is true about DEF?
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When we draw a circle with the centre at D and have a tangent HF to the circle D at point E, the angle DEF will be a right angle.

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