Question

mr. daniels has 1 2/3 acres of land in which he plans to fertilize. if each bag of fertilizer covers 1/9 of an acre and he bought 20 bags, how much will he have leftover?

Answer 1

Area of land that Mr. Daniel has = $1 \frac{2}{3} = \frac{1*3 + 2}{3} = \frac{5}{3}$ Acres.

One Bag of fertilizer cover $\frac{1}{9}$ Acres area.

So area covered by  20 bag of fertilizer will = $20 * \frac{1}{9} = \frac{20}{9}$ Acres.

But Mr. daniel has only $\frac{5}{3}$ Acres area.

So we can say left over area covered by 20 bags = $\frac{20}{9} - \frac{5}{3}$
                                                                                    $= \frac{20 - 15}{9} = \frac{5}{9}$
 
So the left over area covered by 20 bags = $\frac{5}{9}$ Acres.

We know one bag covered $\frac{1}{9}$ acres area.

So number of left over bags = $\frac{ \frac{5}{9} }{ \frac{1}{9} } = \frac{5*9}{1*9} = 5$

So we can say number  of left over fertilizer bags are = 5