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Mekhanik [1.2K]
4 years ago
13

HELPP plz in. 17 thank u so much

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
6 0
In the table, you can see level 1 is 5 to the first power, level 2 is 5 to the second and go on. 
so in level 6 would be 5 to the sixth power
so the answer to first one is 5^6 
for the second question you should know that level 2 is 5^2 and level 6 is 5^6 so 5^6/5^2 = 5^4 is the answer :))))
I hope this is helpful
have a nice day
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I need help solving this word problem
natima [27]

Answer:


Step-by-step explanation:


4 0
4 years ago
What’s the answer? A B C or D
Lorico [155]

The answer is B: 16.9!

Hope this helps!

8 0
3 years ago
Classify the following system of equations.<br><br> 8x - 12y = -9<br><br> 18x + 27y = 21
SSSSS [86.1K]

The following system of equations 8x - 12y = -9   and 18x + 27y = 21 are intersecting lines

<u>Solution:</u>

Given, system of equations are 8x – 12y = - 9 ⇒ (1)

And 18x + 27y = 21 ⇒ 6x + 9y = 7 ⇒ (2)

We have to classify the above given system of equations  

For the we have to find the solution for the given system of equations

So, now, multiply (1) with 9 and (2) with 12, such that both equations will have same coefficients for y terms, such that, it will be easier to find solution while calculations by cancelling.

72x – 108y = - 81

72x + 108y = 84

(+) ---------------------------

144x + 0y = 3

144x = 3

x = \frac{3}{144} = \frac{1}{48}

Substitute "x" value in (2)

\begin{array}{l}{\rightarrow 6\left(\frac{1}{48}\right)+9 y=7} \\\\ {\rightarrow \frac{1}{8}+9 y=7} \\\\ {\rightarrow 1+72 y=56} \\\\ {\rightarrow 72 y=55} \\\\ {\rightarrow y=\frac{55}{72}}\end{array}

So, given system of equations has 1 solution \left(\frac{1}{48}, \frac{55}{72}\right) which means that, they are intersecting lines.

Hence, the given system of equations are classified as intersecting lines

8 0
4 years ago
Perform the indicated operation 3/x+5-2/x-3
poizon [28]

I believe the answer is 2x+1/x

TwoX + one OVER x



HAVE A GOOD DAY!!!!!!!!!!!!

5 0
3 years ago
If we divide x^4+4x^3+2x^2+x+4 by x^2+3x, what will be the remainder?
4vir4ik [10]
If you're familiar with synthetic division, but not the extended form (which allows you easily compute the quotient/remainder when dividing a polynomial by another polynomial of degree greater than 1), then you can perform two steps of SD.

Instead of dividing by x^2+3x, first divide by x, then by x+3 (since x^2+3x=x(x+3)). So we have

0   |   1    4    2    1    4
...  |         0    0    0    0
= = = = = = = = = = = =
...  |   1    4    2    1    4

which translates to

\dfrac{x^4+4x^3+2x^2+x+4}x=x^3+4x^2+2x+1+\dfrac4x

Ignoring the remainder term for now, the next round of SD yields

-3   |   1    4    2    1
...   |        -3   -3    3   
= = = = = = = = = =
...   |   1    1   -1    4

which translates to

\dfrac{x^3+4x^2+2x+1}{x+3}=x^2+x-1+\dfrac4{x+3}

Now, putting everything together, we have

\dfrac{x^4+4x^3+2x^2+x+4}{x^2+3x}=\dfrac{x^3+4x^2+2x+1+\frac4x}{x+3}
=x^2+x-1+\dfrac4{x+3}+\dfrac4{x(x+3)}
=x^2+x-1+\dfrac{4x+4}{x^2+3x}

which is to say the remainder upon dividing x^4+4x^3+2x^2+x+4 by x^2+3x is 4x+4.
5 0
3 years ago
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