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nalin [4]
3 years ago
8

The square root of 1/144 simplified

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0
1/12 is the square root of 1/144
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NEED HELP ASAP THIS IS A TEST<br><br> will mark brainlest <br><br> NO LINKS
Nataly_w [17]
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From quizlet made from balletskye20 with 16 terms
8 0
2 years ago
Factor the expression completely -9.75 + 3.25x
makvit [3.9K]
3.25*(x-3)

Just take out a 3.25
6 0
3 years ago
If x+3 is a factor of x^3-x^2-10x+A. What is the value of A?
Leno4ka [110]

Answer:

A = 6.

Step-by-step explanation:

Let a denote a constant (a number, rather than a variable like x.)

Let f(x) denote an expression about x (for example,

By the factor theorem, if (x - a) is a factor of f(x), then f(a) = 0. In other words, if all mentions of x in the expression f(x)\! are replaced with a, then the expression should evaluate to zero.

(x + 3) is equivalent to (x - (-3)). That is: a = -3.

Replace all mentions of x in x^3 - x^2 - 10\, x + A by (-3) to get:

(-3)^3 - (-3)^2 - 10\times (-3) + A.

That should evaluate to zero. Therefore: -27 - 9 + 30 + A = 0. Solve for A to get A = 6.

7 0
3 years ago
Equation using the quadratic fromula for 0.05x^2 + 1.1x = 250
Anuta_ua [19.1K]

Answer:

x=60.56, x=-82.56

Step-by-step explanation:

Solve using quadratic formula

Formula is

x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

0.05x^2 + 1.1x = 250

Subtract 250 on both sides

0.05x^2 + 1.1x - 250=0

a= 0.05, b=1.1 , c=-250

Plug in the values in the formula

x=\frac{-1.1+-\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}

x=\frac{-1.1+-7.156116265}{0.1}

Now make two equations , one with +  and one with -

then we solve for x

x=\frac{-1.1+7.156116265}{0.1}

x=60.56

x=\frac{-1.1-7.156116265}{0.1}

x=-82.56


3 0
3 years ago
Figure abcd is a parallelogram what are the measures of b and c
Over [174]

what is the question

5 0
3 years ago
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