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Inessa05 [86]
3 years ago
6

Find the first five terms of the following sequence, starting with n=1. tn=(−1)n+1(n2−9) Give your answer as a list, separated b

y commas. For example, if tn=n, you would give your answer as 1,2,3,4,5.
Mathematics
1 answer:
maxonik [38]3 years ago
5 0

Answer:

-8, 5 , 0 , -7 , 16

Step-by-step explanation:

Given

t_n = (-1)^{n+1}(n^2 - 9)

Required

The first five terms

When n = 1

t_1 = (-1)^{1+1}(1^2 - 9)

t_1 = (-1)^{2}(1 - 9)

t_1 = -8

When n =2

t_2 = (-1)^{2+1}(2^2 - 9)

t_2 = (-1)^3 * (4 - 9)

t_2 = 5

t_3 = (-1)^{3+1}(3^2 - 9)

t_3 = (-1)^{4}(9 - 9)

t_3 = 0

t_4 = (-1)^{4+1}(4^2 - 9)

t_4 = (-1)^5(16 - 9)

t_4 = -7

t_5 = (-1)^{5+1}(5^2 - 9)

t_5 = (-1)^{6}(25 - 9)

t_5 = 16

So, the first five terms are: -8, 5 , 0 , -7 , 16

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