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den301095 [7]
4 years ago
12

The two different teaching methods ??

Mathematics
1 answer:
uysha [10]4 years ago
4 0
Two different teaching methods would be visual learning and written learning
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
nikitadnepr [17]

Answer:

The answer should be 45

Step-by-step explanation:

To get the whole are you would have to multiply the lenght with the Width and then take that answer and multiply it with the height

<u>BUT</u>

because you want the surface area, it would be just the lenght and width

15x3=45

so 45 is your answer.

7 0
3 years ago
The engine of a car has a displacement of 305 cubic inches. what is the displacement in cubic feet? round your answer to 2 decim
ipn [44]
 solution
 1 inch = 2.54 centimeters
Therefore, to convert to cubic measurements
 (1 in)³ = (2.54 cm)³
 Thus;
1 in³ = 16.387 cm³
Hence 305 cubic inches will be equivalent to
  305 × 16.387
 = 4998.035 cm³

5 0
3 years ago
Read 2 more answers
I would like to ask about question d
Marrrta [24]
6 halves is 3.
B is at 3 1/2
3 1/2 minus 3 is 1/2
D would be plotted at 1/2.
7 0
3 years ago
Can somebody tell me what 365 times 45 is??
Veseljchak [2.6K]

Answer:

16,425

Step-by-step explanation:

For future references, I'd say use a calculator for multiplication or calculate on a piece of paper. :)

4 0
3 years ago
Read 2 more answers
Please help fast......
Tom [10]

3)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

*************************************************************************************

6)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

*************************************************************************************

7)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}

5 0
3 years ago
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