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mr_godi [17]
3 years ago
6

Can someone help me with my work

Mathematics
1 answer:
juin [17]3 years ago
5 0
F(x) = x
stretch by 3:
f(x) = 3x

flip over x-axis
g(x) = -3x

answer is C. g(x) = -3x


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Plato-Match each set of conditions with the corresponding relationship between ∆ABC and ∆XYZ and the criterion (if any) that pro
Maksim231197 [3]
The first box on the left would be matched with the third box on the right, because the left one is saying that two of the sides are equal, and one angle is equal, therefore, SSA, or SAS.

The second one on the left is matched with the last one on the right, because it says that two of the angles are equal, and one side is equal, hence, AAS, or ASA.

The last one on the left is matched with the first one on the right, because it says all three sides are equal, therefore, SSS. 

The third one on the left is matched with the second one on the left. I'll be honest, I'm not sure why this is, (geometry isn't my best subject either Dx)  but by the process of elimination, this is it.
7 0
3 years ago
Read 2 more answers
Do the ratios 20:18 and 3:2 form a proportion?
DENIUS [597]

Answer:

No.

Step-by-step explanation:

When trying to make this into a proportion, the left and right sides of the equation are unequal, therefore this is invalid.

#learnwithbrainly

#brainliestplease

8 0
2 years ago
Read 2 more answers
1 point) A computer retail store has 11 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the
jekas [21]

Answer: 165 ways

Step-by-step explanation:

The process of selection is done by using the combination formula for selection. If given "n" items and we are to choose "r" items from this given "n", the formula to use is denoted by:

nCr. = n! /(n-r)! × r!

Where

n! = n * (n-1) * (n-2)... *3*2*1.

In this case the number of items given = 11

And the number of items to be chosen = 3,

Hence the number of ways to do this = 11C3= 11!/(11-3)! × 3!

=165 ways.

5 0
3 years ago
How do i write an exponential equation with a vertical asymptote other that y=0
antiseptic1488 [7]
Lets say we have
P(x)/q(x)

vertical assymtotes are in the form x=something, not y=0
y=0 are horizontal assemtotes


so verticall assymtotes
reduce the fraction
set the denomenator equal to zero
those values that make the deomenator zero are the vertical assymtotes

the horizontal assymtote
when the degree of P(x)<q(x), then HA=0

when the degree of P(x)=q(x), then divide the leading coefient of P(x) by the leading coeficnet of q(x)
example, f(x)=(2x^2-3x+3)/(9x^2-93x+993), then HA is 2/9





ok so for vertical assymtote example
f(x)=x/(x^2+5x+6)
the VA's are at x=-3 and x=-2

horizontal assymtote
make degree same
f(x)=(3x^2-4)/(8x^2+9x),
the HA is 3/8
 hope I helped, read the whole thing then ask eusiton

6 0
3 years ago
Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U
lawyer [7]

Answer:

m∠U = 103° and m∠TRS = 6°

Step-by-step explanation:

In the given circle O,

Since, RS║VU, and VR is a transverse,

Therefor, m∠V + m∠R = 180° [Consecutive interior angles]

m∠R + 103° = 180° [m∠R = 103° given]

m∠R = 180° - 103°

m∠R = 77°

Since m∠R = m∠VRT + m∠TRS

77° = 71° + m∠TRS

m∠TRS = 77° - 71° = 6°

Quadrilateral RTUV is a cyclic quadrilateral.

Therefore, m∠U + m∠R = 180°

m∠U + 77° = 180°

m∠U = 180° - 77° = 103°

5 0
3 years ago
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