Take another photo I can’t see that clearly
Answer:
0.026
Step-by-step explanation:
Given the result of 10 coin flips :
T,T,H,T,H,T,T,T,H,T
Number of Heads, H = 3
Number of tails, T = 7
Let :
B = biased coin
B' = non-biased coin
E = event
Probability that it is the biased coin:
P(E Given biased coin) / P(E Given biased coin) * P(E Given non-biased coin) * P(non-biased coin)
P(E|B)P(B) / (P(E|B)*P(B) + P(E|B')P(B')
([(0.75^3) * (0.25^7)] * 0.5) /([(0.75^3) * (0.25^7)] * 0.5) + (0.5^10) * 0.5
0.0000128746 / 0.00050115585
= 0.0263671875
What you do is you combine like terms... so in your instance it is using m.
9m+2= 3m-10
-3m -3m
3m + 2 =-10
+10 +10
3m= 12
m= 4
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2
(-2/5)+x^2, the x values cancel in numerator and denominator and simplify to -2/5
B as it goes through the correct and average amount of points on the graph, hope this helps
