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3 years ago

100 points! Please help me solve these problems!

Mathematics

2 answers:

Lemur [1.5K]3 years ago

5 0

Answer:

Step-by-step explanation:

1.(15c3 + 3c2) ÷ 3c2

=3c2(5c+1) ÷ 3c

=c(5c+1)

2.(d2 - 4d - 77) ÷ (d - 11)

= (d+7)(d-11) ÷ (d - 11)

= d+7

3.(x2 - 12x + 27) ÷ (x - 3)

=(x-9)(x-3) ÷ (x - 3)

= x-9

4.(9p2 + 6p + 1) ÷ (3p + 1)

= (3p+1)(3p+1)÷ (3p + 1)

= 3p+1

5.(4b2 + b - 3) ÷ (b + 1)

= (4b-3)(b+1) ÷ (b + 1)

= 4b-3

Mazyrski [523]3 years ago

4 0

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ 1) (15c^3 + 3c^2) / 3c

3c(5c^2 + c) / 3c

Cancel out the '3c'

= 5c^2 + c

2) (d + 7)(d - 11) / (d - 11)

Cancel out the 'd - 11'

= d + 7

3) (x - 3)(x - 9) / (x - 3)

Cancel out the 'x - 3'

= x - 9

4) (3p + 1)(3p + 1) / (3p + 1)

Cancel out one pair of '3p + 1)

= 3p + 1

5) (4b - 3)(b + 1) / (b + 1)

Cancel out 'b + 1'

= 4b - 3

To get these answers, just factorize the top half and cancel parts out with the denominator.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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