100 points! Please help me solve these problems!
2 answers:
Answer:
Step-by-step explanation:
1.(15c3 + 3c2) ÷ 3c2
=3c2(5c+1) ÷ 3c
=c(5c+1)
2.(d2 - 4d - 77) ÷ (d - 11)
= (d+7)(d-11) ÷ (d - 11)
= d+7
3.(x2 - 12x + 27) ÷ (x - 3)
=(x-9)(x-3) ÷ (x - 3)
= x-9
4.(9p2 + 6p + 1) ÷ (3p + 1)
= (3p+1)(3p+1)÷ (3p + 1)
= 3p+1
5.(4b2 + b - 3) ÷ (b + 1)
= (4b-3)(b+1) ÷ (b + 1)
= 4b-3
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➷ 1) (15c^3 + 3c^2) / 3c
3c(5c^2 + c) / 3c
Cancel out the '3c'
= 5c^2 + c
2) (d + 7)(d - 11) / (d - 11)
Cancel out the 'd - 11'
= d + 7
3) (x - 3)(x - 9) / (x - 3)
Cancel out the 'x - 3'
= x - 9
4) (3p + 1)(3p + 1) / (3p + 1)
Cancel out one pair of '3p + 1)
= 3p + 1
5) (4b - 3)(b + 1) / (b + 1)
Cancel out 'b + 1'
= 4b - 3
To get these answers, just factorize the top half and cancel parts out with the denominator.
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I hope you understood!! :)
Answer:
first question is 112, second is 336
Step-by-step explanation:
you only need to do is 84÷3/4=112calories
this is one box of cereal state if you want three
box calories just 3×112
You should get it now from my previous answer.
But to apply it.
9 - 8b + 6b
9 + (-8b + 6b) <- Collect like bases (b)
9 + (-2b)
9 - 2b
Therefore it simplified is 9 - 2b
Answer:
-14
Step-by-step explanation:
-16 + 2=-14
Answer:
dT/dt = k(T-75)
Step-by-step explanation:
dT/dt = the rate of change of the egg's temperature T with respect to time t
k = constant
(T-75) = difference between the egg's temperature and the room temperature 75 degree
