Answer:
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
Step-by-step explanation:
We will resolve each statement to determine the events that has exactly 12 possible outcomes.
N = number of possible outcomes for a cube
Nc = number of possible outcomes for a coin
Nca = number of possible outcomes for the cards
i. rolling a number cube with sides labeled 1 through 6 and then rolling the number cube again
Nt = N × N
N = 6 ( cube has 6 possible outcomes and its rolled twice)
Nt = 6 × 6 = 36
ii. tossing a coin and randomly choosing one of 4 different cards.
Nt = Nc × Nca
Nc = 2 ( coin has two outcomes)
Nca = 4 ( 4 possible cards )
B = 2 × 4 = 8
iii. rolling a number cube with sides labeled 1 through 6 and tossing a coin.
N = N × Nc
N = 6 ( cube has 6 possible outcomes)
Nc = 2 (coin has two faces)
N = 6 × 2 = 12 (correct)
Iv. tossing a coin 6 times.
N = Nc^6
Nc = 2
N = 2^6 = 64
Therefore, the correct answer is iii.
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
0.03 you just times it by ten or if its a decimal take away the 0 infront of it
By cutting each corner we have that the resulting dimensions are:
27 - 2x
18 - 2x
Height = x
Therefore, the volume of the box in terms of the variable x, is given by:
V (x) = (x) * (27-2x) * (18-2x)
Answer:
The volume of the box in terms of x is:
(27-x) (18-x) x
|-9|, |-3.5|, |4.2| is the answer. row 3
Answer:
B. 138.7
Step-by-step explanation:
Put the given number where the variable is and do the arithmetic.
h(x) = 5.7 -19x
h(-7) = 5.7 -19(-7) = 5.7 +133 = 138.7
