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3 years ago

13

PLZ HELP ME!!!!!! ASAP!!!!! I WILL GIVE BRAINLIEST!!!!!!!!!!!

2 answers:

malfutka [58]3 years ago

8 0

Answer:

(8/15=24/x ) at this point you can do cross multiplication
like this= 8×x and 24×15 which will give you 8x/360
then= 360/8= 45
so x is 45
(5) I don't understand this one so so so so so so so so so much so so so so much so so much so so so so so sorry

Snowcat [4.5K]3 years ago

3 0

Answer:

the answer is

4. x= 45

5. x= 4.5

4. x= 24× 15/8 = 45

5. 72×3/48 = 4.5

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An ellipse has a vertex at (14, –1). The focus of the ellipse nearest that vertex is located at (8, –1). If the center of the el

zavuch27 [327]

Refer to the diagram shown below.

The right vertex is at (14, -1), and the center is at (-1, -1).
Therefore the semi-major axis is
a = 14 - (-1) = 15

The right focus is at (8, -1).
Therefore
c = 8 - (-1) = 9.

The distance of the directrix from the center is
d = c²/a = 9²/15 = 81/15 = 27/5.

Therefore the equation for the left directrix is
x = -1 - 27/5 = -32/5

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3 years ago

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lana [24]

Answer:

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Step-by-step explanation:

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3 years ago

Aleonysh [2.5K]

Answer:

AB // CD and AD // BC, then ABCD is a parallelogram

Step-by-step explanation:

Step 2: Show AD // BC

A = (-3 , 3) and D = (0 , 0)

Find the slope of AD

$m_{AD}=\frac{0-3}{0--3}=\frac{-3}{3}=-1$

B = (2 , 5) and C = (5 , 2)

$m_{BC}=\frac{2-5}{5-2}=\frac{-3}{3}=-1$

The slope of AD = the slope of BC

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3 years ago

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LenaWriter [7]

This is equivalent to -1 ( 4 - 3 )
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3 years ago

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aivan3 [116]

ANSWER:

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EXPLANATIONS:

Diameter of the star = 1.8083 x $10^{4}$ Km.

Surface area of the star = 4 $n^{2}$

Where n is the radius of the star.

So that;

n = $\frac{ 1.8083 * 10^{4} }{2}$

= 0.90415 x $10^{4}$

n = 0.90415 x $10^{4}$ Km

Thus,

Surface area = 4 x $(0.90415*10^{4} )^{2}$

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Therefore, the surface area of the star is 3.2700 x $10^{8}$ square kilometres.

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