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madreJ [45]
3 years ago
12

Bobby bought two shares of stock, which he sold for $96 each. If he had a profit of 20 percent on the sale of one of the shares

but a loss of 20 percent on the sale of the other share, then on the sale of both shares combined Bobby had:____________
a) a profit of $10
b) a profit of $8
c) a loss of $8
d) a loss of $10
e) neither a profit nor a loss
Mathematics
1 answer:
pashok25 [27]3 years ago
8 0

Answer:

The correct option is c) a loss of $8.

Step-by-step explanation:

Consider the provided information.

If the selling price of two item is same and one item sold at a profit of x % and other at a loss of x % in that case total sale result loss:

To calculate the loss use the formula: Loss\ \%=(\frac{x}{10})^2\ \%

It is given that he had a profit of 20 percent on the sale of one of the shares but a loss of 20 percent on the sale of the other share, where the selling price is $96 each.

That means the total sale result will be a loss.

Now use the above formula by substitute x=20.

Loss\ \%=(\frac{20}{10})^2\ \%\\\\Loss\ \%=4\ \%

It is given that the sales price is $96 of each that means total sales price is:

$96+$96=$192

Let the cost price of the shares were x.

According to question: x-4% of x = 192

x-\frac{4}{100}\times x = 192\\\\x-0.04x = 192\\\\0.96x = 192\\x = 200

Hence, the cost price of the shares was 200.

Loss = Cost price -Sales price

Loss = $200 - $192

Loss = $8

Hence, the correct option is c) a loss of $8.

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Answer:

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A train leaves San Diego at 1:00 pm. A second train leaves the same city in the same direction at 3:00 pm. The second train trav
Soloha48 [4]

Answer:

The speed of the first train is 45 mph and the speed of the second train is 75 mph

Step-by-step explanation:

Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).

The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles

The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles

Since the second train overtakes the first at 6:00 pm, hence:

3x + 90 = 5x

2x = 90

x = 45

Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).

7 0
2 years ago
The position d of bicyclist (measured in kilometres) is a linear function of time t (measured in minutes). At time t= 5 minutes,
satela [25.4K]

Answer:

<h2>               21 km    </h2>

Step-by-step explanation:

If the bicyclist travels 7 km for every 5 minutes then it is directly proportional

5 min        7 km

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3 years ago
Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x
egoroff_w [7]

Answer:

y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

<u>Determine the slope (</u><em><u>m</u></em><u>):</u>

y = 1 -2x

Rearrange into slope-intercept form:

y = -2x+1

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of \displaystyle\frac{1}{2}. Plug this into y=mx+b:

y=\displaystyle\frac{1}{2} x+b

<u>Determine the y-intercept (</u><em><u>b</u></em><u>):</u>

y=\displaystyle\frac{1}{2} x+b

Plug in the given point (1,3) and solve for <em>b</em>:

3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}

Therefore, the y-intercept is \displaystyle \frac{5}{2}. Plug this back into y=\displaystyle\frac{1}{2} x+b:

y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}

I hope this helps!

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The confidence interval for proportion is given by :-

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Hence, the 99​% confidence interval for the proportion of returned surveys : (0.355,0.405)

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