3 years ago

Help me writing and solving the inequality for each problem.

Mathematics

1 answer:

MariettaO [177]3 years ago

5 0

They would need to sell 31 bottles

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Find an nth-degree polynomial function<br> n= 3;<br> - 2 and 6 + 2 i are zeros;<br> f(-1)= 53

Bas_tet [7]

Answer:

Find an nth-degree polynomial function.

Step-by-step explanation:

n= 3;

- 2 and 6 + 2 i are zeros;

f(-1)= 53

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2 years ago

Justin and his children went into a bakery and where they sell cookies for $0.75 each and brownies for $1.25 each. Justin has $1

enot [183]

Answer:

Justin could buy up to 8 cookies.

Step-by-step explanation:

7 * 1.25 = 8.75

15 - 8.75 = 6.25

6.25/.75 = 8.3333333

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3 years ago

Shanice's car is traveling 10 miles per hour slower than twice the speed of Brandon's car. She covers 93 miles in 1 hour 30 minu

joja [24]

Shanice's rate: 93 / 1.5 = 62 miles per hour

she is 10 miles slower than twice the speed of Brandon

62 +10 = 72

72/2 = 36

Brandon is driving 36 miles per hour

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3 years ago

If $10,000 is invested at a rate of 2.5 percent for 5 years, how much money is in the account at the end of the term?

Vladimir [108]

10,000(1 + .025 x 5)
11,250

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3 years ago

Read 2 more answers

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

2 years ago