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jok3333 [9.3K]
2 years ago
5

Jocelyn said that the triangle below is not a right triangle. Her work is shown below. Explain what she did wrong and show Jocel

yn the correct solution.

Mathematics
1 answer:
AfilCa [17]2 years ago
8 0

Complete Question:

Jocelyn said that the triangle below is not a right triangle. Her work is shown below. Explain what she did wrong, and show Jocelyn the correct solution.

We need to check if 27² + 45² = 36² is a true statement. The left side of the equation is equal to 2,754. The right side of the equation is equal to 1,296. That means 272 + 452 = 362 is not true, and the triangle shown is not a right triangle

Answer/Step-by-step explanation:

Jocelyn used a wrong equation and statement.

Here's what she should have stated and done.

Using the converse of Pythagorean Theorem, which says that a triangle with sides a, b, and c is a right triangle if it satisfy the statement: a² + b² = c².

Where, c is the hypotenuse which is the longest leg. While a and b are the side lengths of the other two legs.

Therefore, in this case,

c = 45

b = 27

a = 36

Thus, what we need to check to be true would be:

36² + 27² = 45² (this is where Jocelyn made a mistake. Jocelyn wrote 27² + 45² = 36² rather)

Let's check if it's true.

2,025 = 2,025 (this is true)

Therefore, the triangle is a right triangle.

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3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall
Katen [24]

Answer:

The volume of the toy is V=5.23\ ft^3

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

V=\frac{2}{3}\pi r^{3}

In this problem, the wide of the toy is equal to the diameter of the hemisphere

so

D=2\ ft

r=2/2=1\ ft ----> the radius is half the diameter

substitute

V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3

step 2

Find the volume of the cone

The volume of the cone is given by

V=\frac{1}{3}\pi r^{2}h

we know that

The radius of the cone is the same that the radius of the hemisphere

so

r=1\ ft

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

h=4-1=3\ ft

substitute the given values

V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

so

V=(\frac{2}{3} \pi+\pi)\ ft^3

V=(\frac{5}{3}\pi)\ ft^3

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5 0
3 years ago
A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the grou
kotykmax [81]

Answer:

(a) The probability that his height is less than 66 inches is 0.2743.

(b) The probability that the height is between 66 and 71 inches is 0.4679.

(c) The probability that the height is more than 71 inches is 0.2578.

Step-by-step explanation:

The data given in the question is:

Mean (μ) = 68.4

Standard Deviation (σ) = 4

Let X denote the height of men. We will use the normal distribution z-score formula to calculate the z-score and then look up the probability in the normal probability distribution table. The z-score formula is:

z = (X - μ)/σ

(a) For P(X<66), first calculate the z value.

z = (66-68.4)/4

z = -0.6 (Look up this value in the standard normal distribution table)

P(z<-0.6) = 0.2743

The probability that his height is less than 66 inches is 0.2743.

(b) P(66<X<71)  = P(X<71) - P(X<66)

We need to find P(X<71) so, calculating the z-value:

z = (71-68.4)/4

z = 0.65

P(z<0.65) = 0.7422

P(66<X<71)  = 0.7422 - 0.2743

P(66<X<71)  = 0.4679

The probability that the height is between 66 and 71 inches is 0.4679.

(c) To find the probability P(X>71), we need to find P(X<71) and then subtract it from 1 because the normal distribution table gives values for P(X<k). We have already calculated the value of P(X<71) in part (b) so,

P(X>71) = 1 - P(X<71)

            = 1 - 0.7422

P(X>71) = 0.2578

The probability that the height is more than 71 inches is 0.2578.

3 0
3 years ago
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