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Alex Ar [27]
3 years ago
15

45% of the class is girls. There are 90 girls in the class. How many students are in the class?

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

189

Step-by-step explanation:

45% x2= 90%

10% of 90= 9

90+90=180

plus that 10%

180 + 9 = 189

sorry if I'm wrong I'm trying

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Find the length of the line segment shown below.
Marina86 [1]

Answer:

The end points of line segment are:

(x_1,y_1) = (5,4)\\(x_2,y_2)  = (-4,-3)

Using distance formula,

Distance = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} = \sqrt{(-4-5)^{2}+(-3-4)^{2}} = \sqrt{(-9)^{2}+(-7)^{2}} = \sqrt{81+49}=\sqrt{130} units

3 0
3 years ago
the area of a rectangular field is x^2-x-72 m^2. The length of the field is x+8 cm. What is the width of the field meters.
Gre4nikov [31]
Hello,


A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)

We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
 then
only x>9 are solutions)

W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)

5 0
3 years ago
At what x value does the function given below have a hole?<br><br> f(x)=x+3/x2−9
S_A_V [24]

Answer:

hole at x=-3

Step-by-step explanation:

The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)

The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.

So anyways we have (x+3)/(x^2-9)

= (x+3)/((x-3)(x+3))

Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.

4 0
3 years ago
Which step is included in the constitution of inscribed polygons?
Morgarella [4.7K]

I don't know.

you should do it your self not with the internet

3 0
3 years ago
1 – 7k + 3k 2 + 10k + 7 – 5k 2
Katyanochek1 [597]

1) The variables are "k"

2) There are 4 terms

3) The coefficients are k

4) The constants are -7, 3, 10, -5

5) The like terms is -7k, 3k, 10k, -5k

The answers are pretty direct but, hope this answers your question.

Have a great day/night!

8 0
3 years ago
Read 2 more answers
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