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2 years ago

If cos θ= 12 /13 and θ is located in the Quadrant I, find sin (2 θ ), cos(2 θ ), tan(2 θ )

Mathematics

1 answer:

Yakvenalex [24]2 years ago

4 0

Answers: sin(2∅) = 120/169, cos(2∅) = 119/169, tan(2∅) = 120/119

<h3>What are trigonometric functions?</h3>

Trigonometric functions are used to establish the relationship between the sides and the angles of a right angle triangle.

Analysis:

If cos∅ = adjacent/hypotenuse = 12/13,

Then, opposite of the right angled triangle = $\sqrt{13^{2} - 12^{2} }$ = 5

sin∅ = 5/13, cos∅ = 12/13, tan∅ = 5/12

sin(2∅) = 2sin∅cos∅ = 2(5/13)(12/13) = 120/169

cos(2∅) = $cos^{2}$ ∅ - $sin^{2}$ ∅ = $(\frac{12}{13}) ^{2}$ - $(\frac{5}{13} )^{2}$ = 144/169 - 25/169 = 119/169

tan(2∅) = sin(2∅) / cos(2∅) = 120/169 ÷ 119/169 = 120/119

Learn more about trigonometric functions: brainly.com/question/24349828

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3 years ago

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Step-by-step explanation:

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To do this, we make use of the following notations

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So, we have:

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$A = 1000000e^{kt}$

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$ln(0.5) = ln(e^{k*6})$

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$\frac{dA}{dt} = kA$

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$\frac{dA}{dt}$ = Rate

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3 years ago

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Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".

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Plugging in t = 169 gives 2/13 cm3/s.</span>

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