Find an equation of the circle with center at (-2,3) that is tangent to the y-axis in the form of (x-a)^2+(y-b)^2=c where a, b,

Question

Lilit [14]

3 years ago

8

Find an equation of the circle with center at (-2,3) that is tangent to the y-axis in the form of (x-a)^2+(y-b)^2=c where a, b,

c are constants.

Mathematics

1 answer:

xxTIMURxx [149] · Answer 1 · 2022-01-31T15:06:13+03:00

hello :
the center is : (a,b) when : a = - 2 and b= 3
an equation y-axis is x= 0
the ridus is the distance betwen the center and y-axis :
r = |(1)(-2)+(0)(3)+0 |/<span>√((1)²+(0)²) = 2/1 =2
so : c=4.....( c = r²)
</span><span> an equation of the circle is : (x+2)²+(y-3)² = 4</span>