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nasty-shy [4]
3 years ago
7

Tickets for a school play sold for $7.50 for each adult and $3 for each child the total receipts for the 113 tickets sold were $

663 find the number of adult ticket sold
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0
7.5a+3c=663
a+c=113

Write a literal equation for c using the second equation.
c=-a+113

Substitute the value of c into the first equation
7.5a+3(-a+113)= 663
7.5a-3a+339=663
4.5a+339=663
4.5a=324
a=72

Final answer: 72 adult tickets sold

Check by finding the value of c and plugging both values in
(72)+c=113
c=41

7.5(72)+3(41)
663
True
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True [87]

Answer:

64 inch³

Step-by-step explanation:

3 / 2 = 1.5 radius

1.5²x π x 10 = 22.5 π = volume

22.5 π x 9/10 = 20.25π of water

= 63.6172512352

3 0
2 years ago
How do I find 60% of £500?
MA_775_DIABLO [31]

Answer: 300

Step-by-step explanation:

60% = 60/100

500 x 60/100 = 300

8 0
3 years ago
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a recipe uses 1 1/4 cups of milk to make 10 servings. if the same amount of milk is used for each serving, how many servings can
Anestetic [448]

Answer:

128 servings can be made using 1 gallon of milk.

Step-by-step explanation:

Given that:

1\frac{1}{4} cups of milk make 10 servings

1\frac{1}{4} can also be written as 1.25

Ratio of cups of milk to servings = 1.25 : 10

1 gallon = 16 cups

Let,

x be the number of servings made from 1 gallon

Ratio of cups of milk to servings = 16 : x

This is a direct proportion

1.25 : 10 :: 16 : x

Product of mean = Product of extreme

10*16 = 1.25x

160 = 1.25x

1.25x=160

Dividing both sides by 1.25

\frac{1.25x}{1.25}=\frac{160}{1.25}\\x=128

Hence,

128 servings can be made using 1 gallon of milk.

3 0
3 years ago
Slove by using elimination <br> 3x+7y=27 <br> -3x+y=21
tankabanditka [31]

Answer:

x = -5

y = 6

Step-by-step explanation:

3x + 7y = 27      --------------(I)

-3x + y = 21        -----------(II)

Add equation (I) & (II) and so x will be eliminated and we can find the value of y.

(I)      3x + 7y = 27    

(II)    <u> -3x + y = 21  </u>      {add}

                8y = 48

                   y = 48/8

                   y = 6

Plugin y = 6 in equation (I)

3x +7*6 = 27

3x + 42 = 27

       3x = 27 - 42

       3x = -15

         x = -15/3

x = -5

8 0
3 years ago
Urn 1 contains 3 blue tokens and 2 red tokens; urn 2 contains 2 blue tokens and 4 red tokens. All tokens are indistinguishable.
Dmitry_Shevchenko [17]

Answer:

RR = 0.4

RB = 0.3

BB = 0.22

BR = 0.30

Step-by-step explanation:

P( Urn 1 ) = 2/6 = 1/3

P( Urn 2 ) = 1 - 1/3 = 2/3

Urn 1 contains : 3 blue and 2 red

P( blue | urn 1 ) = 3/5 ( with replacement ) , P( blue | urn 1 ) = 3/4 ( without replacement )

P( red | urn 1 ) = 2 / 5 ( with replacement ) , P(red | urn 1 ) = 1/2 ( without replacement )

Urn 2 contains : 2 blue and 4 red

P ( blue | urn 2 ) = 1/3 ( with replacement ) , P( blue | urn 2 ) = 2/5 ( without replacement )

P ( red | urn 2 ) = 2/3 ( with replacement) , P( red | urn 2 ) = 4/5 ( without replacement )

Determine

<u>i) Possible outcomes when two tokens are drawn from either Urn without replacement </u>

RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4

RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3

BB = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.22

BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30

<u />

8 0
3 years ago
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