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frez [133]
3 years ago
10

What is the GCF of 34

Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

2&17

Step-by-step explanation:

34 is a composite number. 34 = 1 x 34 or 2 x 17. Factors of 34: 1, 2, 17, 34. Prime factorization: 34 = 2 x 17.

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The smallest of the 3 circles with center D has a radious of 8 inches
vazorg [7]

Answer:

idkmwjsxuydgcuye

Step-by-step explanation:

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3 years ago
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Gary owns a taco truck. He charges $3.49 for a nacho taco and $4.99 for a cool ranch taco. How much does Gary make if 15 nacho t
Vitek1552 [10]

Answer:

227 dollers

Step-by-step explanation:

multiply 3.49 and 15 to get 52.35

multiply 4.99 and 35 together to get 174.65

then add 52.35 and 174.65 to get the total dollors amounts of 227

8 0
2 years ago
-2y + 6 = -12<br><br> what is the answer??
il63 [147K]

Answer:

9

Step-by-step explanation:

Simplifying

2y + -6 = 12

Reorder the terms:

-6 + 2y = 12

Solving

-6 + 2y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.

-6 + 6 + 2y = 12 + 6

Combine like terms: -6 + 6 = 0

0 + 2y = 12 + 6

2y = 12 + 6

Combine like terms: 12 + 6 = 18

2y = 18

Divide each side by '2'.

y = 9

Simplifying

y = 9

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2 years ago
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Select all the ways you can Solve rates and ratios?​
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find the constant rate of proportionality

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7 0
2 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
3 years ago
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