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frez [133]
3 years ago
10

What is the GCF of 34

Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

2&17

Step-by-step explanation:

34 is a composite number. 34 = 1 x 34 or 2 x 17. Factors of 34: 1, 2, 17, 34. Prime factorization: 34 = 2 x 17.

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Which is true of a geometric plane? A) one-dimensional B) two-dimensional C) three-dimensional D) no dimensions, only position
Sedbober [7]

Answer:

The correct option is B.

Step-by-step explanation:

A plane extends infinitely in two dimensions. It has no thickness.The plane has two dimensions: <u>length and width</u><u>.</u> But since the plane extends infinitely,the length and width cannot be measured.

Lets take an example of a flat sheet of metal. Imagine a flat sheet of metal. Now make it infinitely large in both directions. This means that no matter how far you go, you never reach its edges. Now imagine that it is so thin that it actually has no thickness at all. In spite of this, it remains completely rigid and flat. This is the 'plane' in geometry.

6 0
3 years ago
What is a way to find what 7 is what percent of 20 and I can't use a percent bar model?
Viefleur [7K]

Answer:

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6 0
2 years ago
Find the value of y for the given value of x. Round to the nearest hundredth. y = 15 + 3 ln x; x = 7.2
Nikolay [14]

Answer:

y = 20.922

Step-by-step explanation:

Simply plug in <em>x</em> and evaluate:

y = 15 + 3ln(7.2)

Only way to calculate ln is to plug into a calc:

We should get 20.9222 as our answer.

7 0
3 years ago
A particular computer takes 12 minutes to download a 36​-minute TV show. How long will it take the computer to download a 2​-hou
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7 0
2 years ago
Write the equation of circle b with center B(-2,3) that passes through (1,2)
professor190 [17]

Answer:

(x+2)^2 + (y-3)^2 = 10

Step-by-step explanation:

The standard equation for circle is

(x-a)^2 + (y-b)^2 = r^2

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

(x-a)^2 + (y-b)^2 = r^2    \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2  \\=>(x+2)^2 + (y-3)^2 = r^2    (1)

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 )  in equation 1 we have

\\=>(x+2)^2 + (y-3)^2 = r^2    \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=>  r^2  = 10\\

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is =>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10

7 0
3 years ago
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