Craig had p coins. Then he found 66 more coins in a drawer. Write an expression that shows how many coins Craig has now.
p+ 66
???????what that guy said
The simplest and probably the best way to understand this problem is to make up a problem that obeys what you have been given. It doesn't have to be realistic. It just has to obey the conditions. Let us suppose that you thought the diameter of the tire is 1 yard. That would mean the circumfrence is pi * d
C = 3.14 * 1
That would mean that the circumference is 3.14 yards. It would also mean that you would have to have the wheel turn 1760 yards / /3.14 yards / revolution which is about 561 revolutions / mile. So the way I have set up the problem, my equation is d = 561 * R where R is the number of revolutions.
Now let's see what happens when you say "O my Goodness, the wheel diameter is really 32 inches" which 0.8888888 yards what happens now?
Now you still have to go 1760 yards How many revolutions is that?
C = pi * d
C = 3.14 * 0.88888888
C = 2.79111 yards
How many revolutions does it take to 1760 yards.
R = 1760 // 2.78111 yards / revolution
R = 631 revolutions / mile. What happened?
Your constant goes up if the wheel diameter goes down. Think about this. Do you ride a bicycle? I do. It makes perfect sense to me that if the wheel is small, it will have to turn more often to go a mile. No matter where that 0.00125 comes from or how it was derived, the constant will have to go up if the wheel gets smaller.
Let Home runs = X
Triples would be X-3 ( 3 less triples than home runs)
Doubles would be 3x ( 3 times as many doubles as home runs)
Singles would be 45(x-3) ( 45 times as many singles as triples)
Simplify the equation for singles to be 45x-153
Now you have X + x-3 + 3x + 4x-135 = 262
Simplify:
50x - 138 = 262
Add 138 to both sides:
50x = 400
Divide both sides by 50:
x = 400/50
x = 8
Home runs = x = 8
Triples = x-3 = 8-3 = 5
Doubles = 3x = 3(8) = 24
Singles = 45(x-3) = 45(8-3) = 45(5) = 225
Answer:
The price of the admission is 15.
Step-by-step explanation:
From the information given, you can write the following equations:
a+3e=45 (1)
a+5e=65 (2), where:
a is the admission cost
e is the exhibition cost
First, you can solve for a in (1):
a=45-3e (3)
Second, you can replace (3) in (2):
45-3e+5e=65
45+2e=65
2e=65-45
2e=20
e=20/2
e=10
Finally, you can replace the value of e in (3):
a=45-3e
a=45-3(10)
a=45-30
a=15
According to this, the price of the admission is 15.
