Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
9.2 = x
100 59.95
cross multiply and get 551.54 divided by 100 which is 5.5154
$5.52 of tax is due
0.00067
You always want the period to the right of the first number meaning you’ll start from there counting backwards because it is negative.
Answer:
0
Step-by-step explanation:
use the slope formula <u>y^2-y^1</u>
x^2-x^1
Answer:
B. 56π
Step-by-step explanation:
Circumfrance = 2πr OR πd(r*2)
C = 2π(28) -> C = 56π
OR
C = π(28*2) -> C = 56π
