All categories

3 years ago

What is the length of BC? 18 24 20 22

Mathematics

2 answers:

Radda [10]3 years ago

8 0

Answer:

Step-by-step explanation:

We have the isosceles triangle.

$AC\cong AB$

Therefore we have the equation:

$2x-24=x-2$ add 24 to both sides

$2x-24+24=x-2+24$

$2x=x+22$ subtract x from both sides

$2x-x=x-x+22$

$\boxed{x=22}$

$BC=x$

thereofre

$BC=22$

Alexeev081 [22]3 years ago

4 0

Answer:

Step-by-step explanation:

it shows in the image that AC and AB are isosceles so 2x - 24 would be equal to x - 2

2x - 24 = x -2 ➡ x = 22

You might be interested in

The number of students at maritas school decreased to 98 percent of last years number. Currently, there are 1,170 students. How

Salsk061 [2.6K]

1055 students were in the school last year

8 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago

Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?

Nikolay [14]

Answer:

x = -2, x = 6

Step-by-step explanation:

18 = 3|x - 2| + 6

12 = 3|x - 2|

4 = |x - 2|

4 = x - 2 and -4 = x - 2

x = 6 and x = -2

4 0

3 years ago

Read 2 more answers

Ax^2+bx+c , we get b-c-a=

maria [59]

Answer:

$0 \: I \: think.$

3 0

3 years ago

How to change a number ten by rounding

Llana [10]

10 is already rounded

4 0

3 years ago

Read 2 more answers