Answer:
true
Step-by-step explanation:
Answer:
Step-by-step explanation:
The relation is not a function when x -value is same but y- values are different.
#1
#2
- k^2 - 5k = k + 7
- k^2 - 6k = 7
- k^2 - 6k + 9 = 16
- k - 3 = 4 ⇒ k = 7
- k - 3 = -4 ⇒ k = -1
#3
- k^3 - 5k^2 + 3k = -k
- k^3 - 5k^2 + 4k = 0
- k(k^2 - 5k + 4) = 0
- k = 0, k = 1, k = 4
#4
- |k + 1| + 2 = 8
- |k + 1| = 6
- k = 5, k = -7
Answer:
the student in question bought 3 large notebooks and 3 small notebooks
Step-by-step explanation:
the easiest way to explain how to do this is by recognizing that the student bought $54 worth of notebooks- which is not divisible by 10 easily. that means, we should subtract 8 from 54 until we get a number that IS divisible
54 - 8 = 46 (one small notebook)
46 - 8 = 38 (two small notebooks)
3 8 - 8 = 30 (three small notebooks)
then, divide 30 by 10 to see how many large notebook the student bought.
30/10 = 3
the student in question bought 3 large notebooks and 3 small notebooks
Answer:
3) not equivalent
4) equivalent multiply by 2
5) equivalent multiply by 2
Answer is C as all other choices are even numbers therefore make the equation non-integer.
