All categories

3 years ago

Express each of the following in terms of a reference angle. Explain, please.

1 answer:

4 0

Sin 45 = sin 45
sin 135 = sin (180 - 45) = sin 45
sin(225) = -sin(180 + 45) = -sin 45
sin 315 = -sin(360 - 45) = -sin 45

cos 224.5 = -cos(180 + 44.5) = -cos 44.5
cos 658 = cos(658 - 360) = cos 298 = cos(360 - 62) = cos 62
cos 145.7 = -cos (180 - 34.3) = -cos 34.3
sin (-201) = sin (360 - 201) = sin(159) = sin (180 - 159) = sin 21

You might be interested in

a) Read section 1.5 in the Yakir textbook. If you were a teacher and had 30 students in your class and wanted to know the class

OlgaM077 [116]

Answer:

Parameter

Step-by-step explanation:

Required

Parameter of Statistic

From the question, we understand that the teacher is to calculate the class average.

To calculate the class average, the teacher will use the mean function/formula, which is calculated as:

$Mean = \frac{\sum x}{n}$

Generally, mean is an example of a parameter.

So, we can conclude that the teacher will use parameer

7 0

3 years ago

What is the mathematical name for the object that is defined by the Crocodile River?

kipiarov [429]

The correct answer is : line y=4

6 0

3 years ago

Read 2 more answers

Please help it’s my final

Kryger [21]

Answer:

Step-by-step explanation:

5 0

2 years ago

HELP ME PLEASE!

shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

Find the area of black circle

$r=3/2=1.5\ units$

$x=(3.14)(1.5)^{2} =7.065\ units^{2}$

Find the total area of the square target

$y=9^{2}=81\ units^{2}$

Find the probability

$P=\frac{7.065}{81}=0.0872$

Convert to percentage

$0.0872*100=8.72\%$

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

Find the area of the white portion

The area is equal to the area of the square minus the area of the circle

$x=81-7.065=73.935\ units^{2}$

Find the probability

$P=\frac{73.935}{81}=0.9128$

Convert to percentage

$0.9128*100=91.28\%$

The probability is closer to 1, because is greater than 50%

4 0

3 years ago

Help me and i'll help you earn more points if the question is right

lubasha [3.4K]

-21x^3 - 8x^3 = -29x^3
-7/4x^(1/2) - 0 = -7/4x^(1/2)
-6x^(1/4)
-12x^(-1/2)
12x^(-1/4)
14x^4

Therefore, the correct option is the 2nd one.

6 0

2 years ago