Start with the answer format we want, and work your way toward forming a single fraction like so
Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.
Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.
So, 4+b = 1 leads to b = -3
Therefore, a = 2 and b = -3
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An alternative route:
I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.
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Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.
Approximately 2 gallons will be needed if each gallon of stain and the project will cost be $73.96 if each gallon costs $36.98
<h3>How to find the area of a triangle</h3>
The formula for calculating the area of a triangle is expressed as:
A = 0.5bh
where
base = 15feet
height = 20feet
Area of the deck = 20 * 15 * 0.5
Area of the deck is 150 square feet
Number of gallons needed = 350/150 = 2.3
Hence approximately 2 gallons will be needed if each gallon of stain covers a maximum of 350 square feet.
Cost of the two gallons = 36.98 * 2
Cost of the two gallons = $73.96
Hence the project will cost be $73.96 if each gallon costs $36.98
Learn more on area of a triangle here: brainly.com/question/23945265
Answer:
.24
Step-by-step explanation:
Answer:296 m
I’m assuming “breadth” is width and garderean is just the park.
(25+25+12+12) times 4.
A is never defined
The right answer is Option A.
Step-by-step explanation:
Given equation is;
y = 0.354x+4.669
Where x represents the number of miles traveled.
For measuring the cost for two stations that are 10 miles apart;
x=10
Putting in given equation
Rounding off to nearest hundredth;
y=$8.21
The cost for two stations that are 10 miles apart will be $8.21
The right answer is Option A.
Keywords: linear equation, addition
Learn more about linear equations at:
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