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3 years ago

10

Solve 0.5x^2+6x+5=0

2 answers:

Pie3 years ago

4 0

X=-0.90098048, -11.09901951

Lelu [443]3 years ago

3 0

I hope this helps you

x^2/2+12x/2+10/2=0

x^2+12x+10=0

ax^2+bx+c=0

disctirminant =b^2-4ac

x1,2=-b (-,+) square root of disctirminant /2a

a=1 b=12 c=10

disctirminant = 12^2-4.1.10=144-40=104

x1= -12+square root of 104/2

x2= -12- square root of 104/2

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3 years ago

Need help please thxs

vekshin1

Its option C

40 × (¹/₄)⁰ = 40

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7 0

3 years ago

Solve please I’m stuck

nata0808 [166]

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7 0

3 years ago

Which is the best way to solve the equation?

stiks02 [169]

Option D:

Square both sides of the equation is the best way to solve the equation.

Solution:

Given equation:

$\sqrt{x}=k$

To find which is the best way to solve the equation.

Option A: Multiply both sides of the equation by k.

$\sqrt{x}=k$

$k\sqrt{x}=k^2$

In this method, we are not obtain x value.

It is not true.

Option B: Divide both sides of the equation by k.

$$\frac{\sqrt{x}}{k} =\frac{k}{k}$

$$\frac{\sqrt{x}}{k} =1$

In this method, we are not obtain x value.

It is not true.

Option C: Take the square root of both sides of the equation.

$\sqrt{\sqrt{x}}=\sqrt{k}$

$x^{\frac{1}{4} }=\sqrt{k}$

In this method, we are not obtain x value.

It is not true.

Option D: Square both sides of the equation.

$(\sqrt{x})^2=k^2$

Square and square root get canceled.

$x=k^2$

We obtain x value.

It is true.

Therefore square both sides of the equation is the best way to solve the equation.

Option D is the correct answer.

5 0

4 years ago