All categories

3 years ago

Need some help ya plz

Mathematics

2 answers:

Alex73 [517]3 years ago

6 0

Answer:

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y )

Hence

C(5, 3 ) → C'(- 5, 3 ) → C

erastovalidia [21]3 years ago

3 0

Answer:

C. (-5, 3)

Step-by-step explanation:

Point C is currently (5,3).

If it is reflected over the y-axis, that means while the <em>y-coordinate stays the same, the x- coordinate is negative of what is was before</em>.

C is the only answer that keeps the y-coordinate constant, so just by looking at that, we can say that the answer is C.

You might be interested in

Brian started working at Domino’s in order to build his savings account. He started off with $33 dollars in his account, then ev

iragen [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

18(5−3w) =<br> can someone help me pls

nika2105 [10]

Answer:

90-54w

Step-by-step explanation:

use the distributive property

3 0

3 years ago

Period of f(t)= -2cos(3t)

ivann1987 [24]

Answer:

Period=2pi/3

Step-by-step explanation:

8 0

3 years ago

4[( 8 + 4)10] + 24 devided by 2^3

Nikolay [14]

4[(8+4)10] + 24
so 8 + 4 is 12. Multiply that by 10 and that's 120.
120 + 24 is 144
144 × 4 is 576
for "devided by 2^3" do you mean divided by 2/3?
If so then its 576 ÷ 2/3 = 96

8 0

4 years ago

Find equation of set of points pieces that its distance from the point 3, 4, -5 and -2, 1, 4 are equal.

Gnesinka [82]

Answer:

Step-by-step explanation:

Suppose we a point $P(x,y,z)$ such that its distance from either the point $A(3,4,-5)$ or $B(-2,1,4)$ is the same.

Using this information we can formula:

distance AP = distance BP

first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

$\sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2} = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

3 0

3 years ago