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3 years ago

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Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

The ratio is supposed to be pennies to total amount of coins. The total amount of coins--including pennies--is 16. This can be proven by this equation:

5 + 6 + 5 = 16

Now you put the ratio together by taking the amount of pennies (5) and total amount of coins (16). Your ratio should look like this:

5:16

Hope I helped you out! ❤❤

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The accompanying data represent the daily (for example, Monday to Tuesday) movement of Johnson & Johnson (JNJ) stock for

egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

The lower bound is of 0.484.
The upper bound is of 0.7292.

The interpretation is that we are 95% sure that the true proportion of all days in which the JMJ stock increases is between 0.484 and 0.7292.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

Supposing that it increases on 37 out of 61 days:

$n = 61, \pi = \frac{37}{61} = 0.6066$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292$

The 95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are 95% sure that the true proportion of all days in which the JMJ stock increases is between 0.484 and 0.7292.

A similar problem is given at brainly.com/question/16807970

4 0

2 years ago

Write an exponential function y = ab" whose graph passes through (2,12) and (5,96).

motikmotik

Answer:

y = 3 $(2)^{x}$

Step-by-step explanation:

Substitute the given points into the function and solve for a and b

Using (2, 12)

12 = ab² → (1)

Using (5, 96)

96 = a $b^{5}$ → (2)

Divide (2) by (1)

$\frac{ab^5}{ab^2}$ = $\frac{96}{12}$ , that is

b³ = 8 ( take the cube root of both sides )

b = $\sqrt[3]{8}$ = 2

Substitute b = 2 into (1) and solve for a

12 = a2² = 4a ( divide both sides by 4 )

3 = a

Thus

y = 3 $(2)^{x}$ ← is the exponential function

3 0

3 years ago

Use strips of paper 81/2 inches long. Each strip represents 1 whole. Fold

BlackZzzverrR [31]

Answer:

You didn't tell me what to do

Step-by-step explanation:

6 0

3 years ago

What value of x makes the equation true? A.1 B.-5 C.-1 D.7

Temka [501]

I THINK THE ANSWER IS D.

5 0

3 years ago

I NEED HELP PLEASE ASAP! :)

bonufazy [111]

Answer:

See below.

Step-by-step explanation:

Again, another great question!

This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -

Work = ( 70( cos 50 ) )( 25 ),

Work = ( About ) 1124.87 Joules

The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules

6 0

3 years ago

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