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VARVARA [1.3K]
4 years ago
15

If x/9 < 2/5 and x is a positive integer, how many distinct values are possible for x?

Mathematics
1 answer:
SVEN [57.7K]4 years ago
4 0

Answer:

  3

Step-by-step explanation:

Solving the inequality gives ...

  x/9 < 2/5

  x < 18/5 . . . . multiply by 9

Applying the problem restrictions, we have ...

  0 < x < 3.6 . . . . . x is an integer

Solutions are {1, 2, 3}. There are 3 distinct possible values for x.

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