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alekssr [168]
2 years ago
12

Rewrite using a single positive exponent. 7^9 x 7^-2

Mathematics
1 answer:
lidiya [134]2 years ago
6 0

Answer:

7^7

Step-by-step explanation:

When you multiply exponents with the same base, you add the exponents

Hope it helped!

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What are the slope and y-intercept of the graph of this equation?
schepotkina [342]

Answer:

slope = y = 1/2

y-intercept = b = -3

Step-by-step explanation:

slope intercept equation:

y = mx + b----->(equation 1)

m is slope

b is y-intercept

y = 1/2x - 3----->(equation 2)

Compare (equation 1) and (equation 1)

slope = y = 1/2

y-intercept = b = -3

3 0
2 years ago
How can you determine which of two lines will be steeper from
Romashka-Z-Leto [24]
Well on a table of data, if the y coordinates increase a lot over a short x distance then it will be steep.

In an equation, you would put it into y = mx + b form and whatever your m is will be your slope. If m is large, it will be steep.
8 0
3 years ago
I need help with this question, it asks for what property each equation is, the answers i put are random. thank you very much if
Olegator [25]

1) addition property , you add the -3 over

2) division property , you divide by 6x

3)multiplication property , multiply the 3 by 5 to solve for x .

5 0
2 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
May i have help with this
Leya [2.2K]

Answer: D. 7^11

Step-by-step explanation:

For exponents with the same base, we just add the exponents and keep the same base. 7 is the same base; therefore 5+6=11 which means the answer is 7^11

3 0
2 years ago
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