24% of 289= <br> Estimate using a rate per 100

Two types of barrel units were in use in the 1920s in the United States. The apple barrel had a legally set volume of 7056 cubic

babymother [125]

Answer:

Discrepancy = 665,15 L

Step-by-step explanation:

Data: 1 Apple Barrel: 7056 cubic inches

1 Cranberry Barrel: 5826 cubic inches

The merchant sells 33 cranberry barrels, so we need to find out the total volume of that. So we multiply our cranberry volume (data) 33 times:

33 x 5826 cubic inches = 192258 cubic inches

Now, the customer thinks that he is receiveing apple barrels. To calculate this volume, we need to multiply the apple volume (data) 33 times:

33 x 7056 cubic inches = 232848 cubic inches

(You can see that 33 apple barrels have more volume that 33 cranberry barrels, so the customer will receive less volume than he is expecting)

The problem is asking the discrepancy in the shipment in liters (L). First we calculate the discrepancy (difference) in cubic inches.

Discrepancy (cubic inches) = 232848 cubic inches - 192258 cubic inches = 40590 cubic inches

Finally we need to transform the units. As a general rule, we know that:

1 litre (L) = 61,0237 cubic inches. Using a simple rule of three we can solve it:

Discrepancy (L) = $\frac{40590 cubic inches}{61,0237 cubic inches\\}$ x 1 L

Discrepancy (L) = 665,15 L

7 0

3 years ago

I will give you brainlist if you answer it.

blsea [12.9K]

Answer:

D or A not sure yet

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

GuDViN [60]

Answer:

Euler's method is a numerical method used in calculus to approximate a particular solution of a differential equation. As a numerical method, we have to apply the same procedure many times, until get the desired result.

In first place, we need to know all the values the problem is giving:

The step size is 0.2; h = 0.2. This step size is a periodical increase of the x-variable, which will allow us to calculate each y-value to each x.
The problem is asking the solution y(1), which means that we have to find the y-value assigned for x = 1, through the numerical method.
The initial condition is y(0) = 9. In other words, $x_{o} = 0\\y_{0}=9$ .

So, if the initial x-value is 0, and the step size is 0.2, the following x-value would be: $x_{1}=0.2$ ; then $x_{2}=0.4$ ; $x_{3} =0.6; x_{4} =0.8;x_{5} =1$ ; and so on.

Now, we have to apply the formula to find each y-value until get the match of $x_{5}=1$ , because the problem asks the solution y(1).

According to the Euler's method:

$y_{1} =y_{0} +hF(x_{0};y_{0})\\y_{2} =y_{1} +hF(x_{1};y_{1})\\y_{n} =y_{n-1} +hF(x_{n-1};y_{n-1})$

Where $F(x;y)=x^{2} y-12y^{2}$ , and $x_{0} =0; y_{0} =9$ ; $h=0.2$ .

Replacing all values we calculate the y-value assigned to $x_{1}$ :

$y_{1} =9+0.2((0)^{2} 9-12(9)^{2})=-185.4$ .

Now, $y_{1} =-185.4$ , $x_{1} =0.2; h=0.2$ . We repeat the process with the new values:

$y_{2} =y_{1} +hF(x_{1};y_{1}) \\y_{2} = -185.4+0.2((0.2)^{2} (-185.4)-12(-185.4)^{2} )\\y_{2}=-82682.47$

Then, we repeat the same process until get the y-value for $x_{5} =1$ , which is $y_{5} = -1.0018$ , round to four decimal places.

Therefore, $y(1)=-1.0018$ .

7 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. <br> IM GIVING 40 POINTS !! DONT SKIP :((.

Artist 52 [7]

Answer:

y = 2x - 81

Step-by-step explanation:

8 0

2 years ago

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
$

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
$\frac{-77+21i}{130}$

7 0

3 years ago

24% of 289= Estimate using a rate per 100