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Dmitry_Shevchenko [17]
3 years ago
7

A cylinder’s radius is reduced to 2004-06-01-04-00_files/i0480001.jpg its original size and the height is quadrupled. How has th

e volume of the cylinder changed?
Mathematics
1 answer:
asambeis [7]3 years ago
6 0
I can't answer this question if we don't know by what scale the cylinder's radius was reduced. Luckily, I found the same problem that says the radius was reduced to 2/5. So, we find the ratio of both volumes.

V₁ = πr₁²h₁
V₂ = πr₂²h₂

where r₂ = 2/5*r₁ and h₂ = 4h₁

V₂/V₁ = π(2/5*r₁ )²(4h₁)/πr₁²h₁= 8/5 or 1.6

<em>Thus, the volume has increased more by 60%.</em>
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What sum of money amounts to rupees 8700 in 3 years at the rate of 24 % per annum​
Zina [86]

Given:

Amount = 8700

Time = 3 years

Rate of interest = 24% per annum

To find:

The principal values.

Solution:

Formula for amount:

A=P\left(1+\dfrac{r}{100}\right)^t

Where, A is amount, P is principal, r is the rate of interest and t is the number of years.

Putting A=8700,r=24,t=3, we get

8700=P\left(1+\dfrac{24}{100}\right)^{3}

8700=P\left(1+0.24\right)^{3}

8700=P\left(1.24\right)^{3}

8700=1.906624P

Divide both sides by 1.906624.

\dfrac{8700}{1.906624}=P

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Answer:

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Step-by-step explanation:

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oksian1 [2.3K]
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Assume, for the sake of this question, that the data were collected through a well-designed, well-implemented random sampling me
amid [387]

Answer:

Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.

Step-by-step explanation:

The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.

This means that at the null hypothesis we test if the proportion is at least 60%, that is:

H_{0}: p \geq 0.6

And the alternate hypothesis is:

H_{a}: p < 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that:

\mu = 0.6

\sigma = \sqrt{0.6*0.4}

Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.

This means that n = 575, X = \frac{338}{575} = 0.5878

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}

z = -0.6

Pvalue of the test and decision:

We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.

Looking at the z-table, z = -0.6 has a pvalue of 0.2743.

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Simplify fully<br> 8<br> x<br> 12<br> x<br> 2<br> y
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Answer:

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