Question

A theater charges $50 per ticket for seats in section a, $40 per ticket for seats in section b, and $20 per ticket for seats in section
c. for one play, 9,500 tickets were sold for a total of $335,000 in revenue. if 500 more tickets in section b were sold than the other two sections combined, how many tickets in each section were sold?

Answer 1

The first thing we must do for this case is to define variables.
 We have then:
 x: ticket for seats in section a
 y: ticket for seats in section b
 z: ticket for seats in section c
 We write the system of equations:
 50x + 40y + 20z = 335000
 x + y + z = 9500
 y = x + z + 500
 Solving the system we have:
 x = 1500
 y = 5000
 z = 3000
 Answer:
 ticket for seats in section a = 1500
 ticket for seats in section b = 5000
 ticket for seats in section c = 3000