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3 years ago

10

(a) Complete the last column of the following table by calculating the estimated number of messages per day that each user recei

ves. Round to the nearest
tenth
Year
Number of users Messages per day Messages per person
(in millions) (In billions)
per day
2012
2,852
220.8
2019
3,192
243.9
2021
3,480
275.7

1 answer:

Andrej [43]3 years ago

5 0

Answer:

kj

Step-by-step explanation:

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The speedy punt returner and the ferocious defensive player are headed straight toward each other. The punt returner is travelin

Svetach [21]

Answer:

2

Step-by-step explanation:

15+12=27

54 / 27 = 2

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3 years ago

Find the place value of 8 in 2456.1387.<br> Tenths<br> Hundredths<br> Thousandths<br> Thousands

rjkz [21]

Answer: Third Choice. Thousandths

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the order and name of each place value.

Please refer to the attachment below for the specified names.

<u>Solve:</u>

<em>STEP ONE: Orde and name each place</em>

2 ⇒ One Thousands

4 ⇒ Hundreds

5 ⇒ Tens

6 ⇒ Ones

.

1 ⇒ Tenths

3 ⇒ Hundredths

8 ⇒ One Thousandths

7 ⇒ Ten Thousandths

<em>STEP TWO: Find the number [8] in the number</em>

As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is <u>Thousandths</u>.

Hope this helps!! :)

Please let me know if you have any questions

5 0

3 years ago

I will mark brainliest

Novosadov [1.4K]

Answer: 48.54101966249685

Step-by-step explanation:

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3 years ago

Read 2 more answers

A norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. Find the dimensions of a norman

Yanka [14]

Answer:

$W\approx 8.72$ and $L\approx 15.57$ .

Step-by-step explanation:

Please find the attachment.

We have been given that a norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. The total perimeter is 38 feet.

The perimeter of the window will be equal to three sides of rectangle plus half the perimeter of circle. We can represent our given information in an equation as:

$2L+W+\frac{1}{2}(2\pi r)=38$

We can see that diameter of semicircle is W. We know that diameter is twice the radius, so we will get:

$2L+W+\frac{1}{2}(2r\pi)=38$

$2L+W+\frac{\pi}{2}W=38$

Let us find area of window equation as:

$\text{Area}=W\cdot L+\frac{1}{2}(\pi r^2)$

$\text{Area}=W\cdot L+\frac{1}{2}(\pi (\frac{W}{2})^2)$

$\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W}{2})^2)$

$\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W^2}{4})$

$\text{Area}=W\cdot L+\frac{\pi}{8}W^2$

Now, we will solve for L is terms W from perimeter equation as:

$L=38-(W+\frac{\pi }{2}W)$

Substitute this value in area equation:

$A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2$

Since we need the area of window to maximize, so we need to optimize area equation.

$A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2$

$A=38W-W^2-\frac{\pi }{2}W^2+\frac{\pi}{8}W^2$

Let us find derivative of area equation as:

$A'=38-2W-\frac{2\pi }{2}W+\frac{2\pi}{8}W$

$A'=38-2W-\pi W+\frac{\pi}{4}W$

$A'=38-2W-\frac{4\pi W}{4}+\frac{\pi}{4}W$

$A'=38-2W-\frac{3\pi W}{4}$

To find maxima, we will equate first derivative equal to 0 as:

$38-2W-\frac{3\pi W}{4}=0$

$-2W-\frac{3\pi W}{4}=-38$

$\frac{-8W-3\pi W}{4}=-38$

$\frac{-8W-3\pi W}{4}*4=-38*4$

$-8W-3\pi W=-152$

$8W+3\pi W=152$

$W(8+3\pi)=152$

$W=\frac{152}{8+3\pi}$

$W=8.723210$

$W\approx 8.72$

Upon substituting $W=8.723210$ in equation $L=38-(W+\frac{\pi }{2}W)$ , we will get:

$L=38-(8.723210+\frac{\pi }{2}8.723210)$

$L=38-(8.723210+\frac{8.723210\pi }{2})$

$L=38-(8.723210+\frac{27.40477245}{2})$

$L=38-(8.723210+13.70238622)$

$L=38-(22.42559622)$

$L=15.57440378$

$L\approx 15.57$

Therefore, the dimensions of the window that will maximize the area would be $W\approx 8.72$ and $L\approx 15.57$ .

8 0

3 years ago

Compare the pair of fractions. ( <,>,=) <br> 3/4__5/6

Andrew [12]

Answer:

3/4 is less < than 5/6

Step-by-step explanation:

4 0

3 years ago