Answer=140 fish
200 gallons of water in the first aquarium.
200 gallons of water in the second aquarium.
The first will be for the small fishes.
5 small fish x fish
_____________=__________
10 gallons 200 gallons
cross multiply
10x=1000
divide both sides by 10
x=100 small fish
The first aquarium has 100 small fish.
The second aquarium holds large fish.
8 large fish x fish
____________=___________
40 gallons 200 gallons
cross multiply
40x=1600
divide both sides by 40
x=40 large fish
The second aquarium has 40 large fish.
100small fish+40 large fish=140 total fish
Answer: B.98
Step-by-step explanation:
all you have to do is divide 1,176 by 12.
Answer: 0.9104
Step-by-step explanation:
Given : A hardware store receives a shipment of bolts that are supposed to be 12 cm long.
Mean : 
Standard deviation : 
Sample size : n=10
Since, they will declare the shipment defective and return it to the manufacturer if the average length of the 100 bolts is less than 11.97 cm or greater than 12.04 cm.
So for the shipment to be satisfactory, the length of the bolts must be between 11.97 cm and 12.04 cm.
We assume that the length of the bolts are normally distributed.
Let X be the random variable that represents the length of randomly picked bolt .
For Z score : 
For x = 11.97

For x = 12.04

By using the standard normal distribution table , the probability that the shipment is found satisfactory will be :-

Hence, the probability that the shipment is found satisfactory=0.9104
Answer:
y= total cost
x= per person
y=10x+a
well we know this equation so
32.25=10(3)+a
a=2.25
Step-by-step explanation:
<u>well 8 divided by 4 is 2 and 11-8+2 is 5 and 5 times 4 is 20 so 20 is the answer
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