The answer is B. Fabiana has completed the same amount of the course as Samantha because 6/15=8/20. Both fractions reduce to 2/5. Therefore, they are equivalent.
Answer:
1) 16
2a) 100 -a -2b
2bi) (100 -a -2b)/4
2bii) 11
Step-by-step explanation:
1. Put the numbers where the corresponding variables are and do the arithmetic.
(2(1) +3(-2))^2 = (2 -6)^2 = (-4)^2 = 16
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2. The pieces cut from the wire have the lengths a, b, b. The sum of those lengths is a+b+b = a+2b.
2a. The remaining length is what is left when the total of cut pieces is subtracted from the original amount:
100 -(a+2b) = 100 -a -2b
2bi. The perimeter of the square is the amount in part (2a). A square has 4 sides of the same length, so each side has a length that is 1/4 of the perimeter. The side length is ...
(100 -a -2b)/4 . . . . length of one side of the square
2bii. Fill in the given values for "a" and "b" and do the arithmetic.
(100 -24 -2(16))/4 = (76 -32)/4 = 44/4 = 11 . . . one side of the square
Answer:
Step-by-step explanation:
m= 1/2
this is answer ..........
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Answer:
Polygon q’s area is one fourth of polygon p’s area
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> polygon q’s area
y-----> polygon p’s area
so

In this problem we have

substitute



therefore
Polygon q’s area is one fourth of polygon p’s area