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Tresset [83]
3 years ago
12

What is six less than 9

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

3

Step-by-step explanation:

9-6=3

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If a day of the week is randomly selected, what's the probability that the day contains the letter "a" in its name?
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1

Step-by-step explanation:

monday, tuesday, wednesday, thursday, friday, saturday, and sunday all have "a" in it so it has a 100% probability

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Find the distance between the points (4,-2), (4,-5)
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\text{Given that,}\\\\(x_1,y_1) = (4,-2)~~ \text{and}~~  (x_2 ,y_2) = (4,-5)\\\\\text{Distance} = \sqrt{(x_2-x_1)^2 + (y_2 -y_1)^2}\\\\~~~~~~~~~~~~=\sqrt{(4-4)^2 + (-5+2)^2}\\\\~~~~~~~~~~~~=\sqrt{0^2+(-3)^2}\\\\~~~~~~~~~~~~=\sqrt{0+9}\\\\~~~~~~~~~~~~=\sqrt 9\\\\~~~~~~~~~~~~=3

6 0
2 years ago
7W + 3 = -4W - 85 <br><br>a. -11<br>b. 11<br>c. 8<br>d. -8<br>​
mylen [45]
-8
Step 1) Subtract 3 from both sides of the equation
Step 2) Add 4W to both sides of the equation
Step 3) Divide both sides of the equation by the same factor
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2 years ago
For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co
Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b)   Margin of error ( E) = $1,000 , n = 216

(c)   Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation \sigma = $7,500

\alpha = 1 - confidence interval = 1 - .95 = .05

Z_{\frac{\alpha}{2}} =  Z_{\frac{.05}{2}} = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E)  = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

                           E   = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}

n =  54.0225

n = 54 ( approximately)

(b)   Margin of error ( E) = $1,000

          E     = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

         1000   =  Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}

n = 216

(c)   Margin of error ( E) = $500

   E = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

  500 = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}

n = 864

7 0
3 years ago
What is the value of X
andrezito [222]
The value of x is X=7
3 0
3 years ago
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