What is the variance of the values 8,10,14,12?

The square, the rectangle and the rhombus are in the quadrilaterals group (shapes or figures with four sides) and in the parallelogram sub-group (shapes or figures with four sides in which opposite sides are parallel).

In other words,

<h2>what these three shapes have in common is that they are Parallelograms.</h2>

Hence, they have the same properties of a parallelogram, such as:

1. Opposite sides parallel and with the same length

2. Opposite angles are congruent (equal angles, or angles with the same value)

3. Consecutive angles are supplementary (angles that add up to 180°)

Also the general properties of a quadrilateral:

1. It has four sides

2. It is a 2-dimensions shape

3. It is a closed figure

4. It has four corners (called vertices), and four interior angles, as well.

5. The sum of their four interior angles is 360º

b. How are these two shapes different?

In this case we are going to talk about the differences between the Rectangle and the Rhombus, because the square is a special case of both.

Now, the differences between the Rectangle and the Rhombus are:

1. In the Rectangle only the opposite sides are of the same length, while in the rhombus all of its sides are of the same length.

2. If you trace two diagonal lines inside the Rectangle, they will have the same length. But if you trace two diagonal lines inside the Rhombus they will have different lengths.

3. When the two diagonals in the Rectangle are intersected, they are not perpendicular, but in the case of the Rhombus they are perpendicular (both lines form an angle of 90º)

4. All the angles of the rectangle have the same value: 90º. But in the case of the rhombus only the opposite angles have the same value.

c. What conclusion can you make about the square, rhombus and rectangle?

These three shapes belong to the parallelogram group (which is also part of the quadrilaterals group). They have a lot of things in common for being quadrilaterals, with some differences related to their own shape.

The square is a special case of these three figures, is a rhombus (four equal sides) and a rectangle (four equal 90º angles), as well.

5 0

3 years ago

A card is drawn at random from a standard deck of 52 cards. Find the following conditional probabilities. a) The card is a diam

Inga [223]

Answer:

$a.\frac{1}{13}\\b.\frac{1}{2}\\c.\frac{1}{13}\\d.\frac{1}{13}$

Step-by-step explanation:

P(A|B) = P(A and B) / P(B)

Total number of cards = 52

a)

Let A denotes the event that the card is a diamond and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}\\=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

b)

Let A denotes the event that the card is red and B denotes the card is diamond.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{4}{52}}\\=\frac{1}{2}$

c)

Let A denotes the event that the card is nine and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

d)

Let A denotes the event that the card is a king and B denotes the card is a face card.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{4}{52}}{\frac{12}{52}}\\=\frac{1}{13}$

7 0

3 years ago

What is the prime factorization if 6400 using exponents

katovenus [111]

So prime factorization is as it seems, finding the prime factors for a number. With this number, break it down as such:

$\underbrace{6400}_{\underbrace{64}_{\underbrace{8}_{\underbrace{4}_{\boxed{2*2}} \boxed{2}}*\underbrace{8}_{\underbrace{4}_{\boxed{2*2}}\boxed{2}}}*\underbrace{100}_{\underbrace{10}_{\boxed{5*2}}*\underbrace{10}_{\boxed{5*2}}}}$

Looking at our factors, the prime factorization of 6400 is $2^8*5^2$ 

5 0

3 years ago