Answer:
y=2e^(−x)cosx−e^(−x)sinx
Satisfies the equation
Step-by-step explanation:
Answer:
y=2e^(−x)cosx−e^(−x)sinx
y = e^(-x)[2cosx - sinx]
Find y' and y" using product law
y' = -e^(-x)[2cosx - sinx] + e^(-x)[-2sinx - cosx]
y' = -e^(-x)[2cosx - sinx + 2sinx + cosx]
y' = -e^(-x)[3cosx + sinx]
y" = e^(-x)[3cosx + sinx] - e^(-x)[-3sinx + cosx]
y" = e^(-x)[3cosx - cosx + sinx + 3sinx]
y" = e^(-x)[2cosx + 4sinx]
y" + 2y' + 2y
e^(-x)[2cosx + 4sinx] - 2e^(-x)[3cosx + sinx] +2e^(-x)[2cosx - sinx]
e^(-x)[4sinx - 2sinx - 2sinx + 2cosx - 6 cosx + 4cosx]
= e^(-x) × 0
= 0
Answer:
B, C, D
Step-by-step explanation:
9x4=36 Yes
12x3=36 Yes
6x6=36 Yes
9x9=81 No
8x4=32 No
The distributive property lets you expand the product as
Answer:
(5+x)/x
Step-by-step explanation:
Given
h(x)= 5+x
k(x)= 1/x
(koh)(x)=?
Here you multiply
1/x( 5+x)
5/x +x/x
5/x+1 or
5/x +x/x
(5+x)/x
Answer:
1/3
Step-by-step explanation:
1/3 can be used as an expression that is exactly the same as 2/3x5.
When you multiply 2/3 x 5-
Look here if you need help solving 2/3 X 5: (2/3 x 5/1...is the simplest way to multiply the two, make sure to multiply 2 by 5 and 3 by 1 to get your answer.)(5x2=10...3x1=3)
-you get 10/3. This answer simplified is 1/3. So in the end, 1/3 is a great expression or answer to use as an equivalent to the equation 2/3 x 5.
Hoped this helped! :)
