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Artist 52 [7]
3 years ago
6

Modern medical advances might mean people could live 200 years. inâ 2009, the life expectancy is about 80 years. assumeâ that, d

ue to modernâ advances, life expectancy gains 5.4 years every decade. fromâ 2009, in how many years would humanity achieve a life expectancy of 130 âyears?
Mathematics
1 answer:
olga2289 [7]3 years ago
6 0
For this problem, we have to set up the formula for the equation first. The equation should help us predict how long would it take to reach a life expectancy of 130 years. Let's start by denoting variable to present them in algebraic equations. Let x be the number of decades, while y is the number of years for life expectancy. The base year used here is 2009 with a life expectancy of 80 years. So, we will expect that 80 is a constant in the expression. We will add to this the number of decades multiplied by 5.4, because it stands for 5.4 additional years per decade. When you write this in an equation, it would be

y = 80 + 5.4x

Now, we substitute y=130.

130 = 80 + 5.4x
x = (130 - 80)/5.4
x = 9.259 

Therefore, it would take approximately more than 9 decades. Projecting this amount of time from 2009, the year would be:

Projected year = 2009 + 9 decades * (10 years/1 decade)
Projected year = 2101

It would be in year 2101.
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Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

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If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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