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Brums [2.3K]
3 years ago
9

Find the value of x in the triangle shown above ​

Mathematics
1 answer:
zalisa [80]3 years ago
5 0
The answer is A. 4
in this equation you use pythagoreans theorem

x^2-8^2=9^2

x^2-64=81

81-64=17

square x^2 square 17

x=4.12 rounded to 4
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Step-by-step explanation:

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The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).
Effectus [21]

Answer:

\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}

Step-by-step explanation:

Given the quadratic equation as:

2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0

Let us put sinx=y for simplicity of the equation:

Now, the equation becomes:

2y^2+y-1=0

Now, let us try to solve the quadratic equation:

\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1

So, the solution to the given trigonometric quadratic equation is:

sinx = \dfrac{1}{2}

and

sinx=-1

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sin\theta can have a value equal to \frac{1}{2} in 1st and 2nd quadrant.

So, x can be

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x = 270^\circ\ or\ \dfrac{3 \pi}{2}

So, the answer is:

\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}

7 0
3 years ago
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