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2 years ago

1/2 x + y = 8 and 2y = x + 14 pls show your work thx

Mathematics

1 answer:

Fudgin [204]2 years ago

3 0

9514 1404 393

Answer:

(x, y) = (1, 7.5)

Step-by-step explanation:

Solve the first equation for y, then substitute into the second equation.

y = 8 -1/2x . . . . . subtract 1/2x

2(8 -1/2x) = x +14

16 -x = x + 14 . . .eliminate parentheses

2 = 2x . . . . . . . add x-14

1 = x . . . . . . . . divide by 2

y = 8 -1/2(1) = 7 1/2

The solution is (x, y) = (1, 7 1/2).

<em>Alternate solution</em>

Type the equations into a graphing calculator and let it show you the solution.

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<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

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<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x + 8

Expand the equation

x^2 + 6x + 8 = x^2 + 4x + 2x + 8

Factorize the equation

x^2 + 6x + 8 = (x + 2)(x + 4)

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