That's of course the 30/60/90 right triangle.
If you need to see the algebra, the acute angles in a right triangle are complementary, adding to 90 degrees:
x + 2x = 90
3x = 90
x = 30
<h3>Answers :-</h3>
- sinB = 12/13
- cosB = 5/13
- tanB = 12/5
Here as by the given information ,
♦ sinA = Opposite/Hypotenuse
♦ cosA = Adjacent/Hypotenuse
♦ TanA = Opposite/adjacent
So here we need to find the same for angle B so we need to use the same formulas for angle B also .
→ sinB = Opposite/Hypotenuse = 12/13
→ cosB = Adjacent/Hypotenuse = 5/13
→ tanB = Opposite/Adjacent = 12/5
The function's domain are all of the "x" values or "k" values in this case that will satisfy the function's range. Hence, you should solve for k after that to get the function's domain after substituting for the function's range.
Quadratic in equality is quadratic function that is compared to another function like: x^2+4x-1<2x-3. the answer for x must comply to both sides.
Answer:
9 and 15
Step-by-step explanation:
9 10 11 12 13 14 15